The volume strength of 1.5 N is
- A.4.8
- B.8.4
- C.3.0
- D.8.0
Show answer and solution
Correct option: B
Solution
For H₂O₂, normality = 2 × molarity (since n-factor = 2).
So molarity = 1.5/2 = 0.75 M.
Volume strength = molarity × 11.2 = 0.75 × 11.2 = 8.4.
(This factor 11.2 comes from the fact that 1 mole of H₂O₂ releases 11.2 L of O₂ at STP.)
So molarity = 1.5/2 = 0.75 M.
Volume strength = molarity × 11.2 = 0.75 × 11.2 = 8.4.
(This factor 11.2 comes from the fact that 1 mole of H₂O₂ releases 11.2 L of O₂ at STP.)
[1990]