JEE Main 2019 · 12 April · Shift I

JEE Main 2019 Mathematics question on Limits Continuity and Differentiability

Let f:R→Rf: R \to R be a continuously differentiable function such that f(2)=6f(2) = 6 and f′(2)=148f'(2) = \frac{1}{48}. If ∫6f(x)4t3 dt=(x−2)g(x)\int_6^{f(x)} 4t^3 \, dt = (x-2)g(x), then lim⁡x→2g(x)\lim_{x \to 2} g(x) is equal to
  1. A.
    18
  2. B.
    24
  3. C.
    12
  4. D.
    36
Show answer

Correct option: A

[JEE Main 2019 · 12 April · Shift I]

Practise Limits Continuity and Differentiability the way it is asked

A timed set of real JEE Main Limits Continuity and Differentiability questions, graded as the exam grades. No sign-up.

Start a Limits Continuity and Differentiability test

More: all JEE Main Limits Continuity and Differentiability questions · JEE Main 2019 · Mathematics chapter list