If the function f defined on ((π)/6, (π)/3 ) by f(x) = begincases dfrac√(2)cos x - 1cot x - 1, & x ≠ (π)/4 \ k, & x = (π)/4 endcases is continuous, then k is equal to

If the function f defined on ((π)/6, (π)/3 ) by f(x) =… — JEE Main 2019 Mathematics PYQ

JEE Main 2019 · 9 Apr · Shift I

If the function

f

defined on

\left(\frac{\pi}{6}, \frac{\pi}{3}\right)

f(x) = \begin{cases} \dfrac{\sqrt{2}\cos x - 1}{\cot x - 1}, & x \neq \dfrac{\pi}{4} \\ k, & x = \dfrac{\pi}{4} \end{cases}

is continuous, then

k

is equal to

Show answer

Correct option: A

[JEE Main 2019 · 9 Apr · Shift I]

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