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JEE Main 2019 · 8 Apr · Shift II

JEE Main 2019 Mathematics question on Limits Continuity and Differentiability

Let f:R→Rf: R \to R be a differentiable function satisfying f′(3)+f′(2)=0f'(3) + f'(2) = 0. Then lim⁡x→0(1+f(3+x)−f(3)1+f(2−x)−f(2))1x\lim_{x \to 0} \left(\frac{1 + f(3+x) - f(3)}{1 + f(2-x) - f(2)}\right)^{\frac{1}{x}} is equal to
  1. A.
    ee
  2. B.
    e−1e^{-1}
  3. C.
    e2e^2
  4. D.
    11
Show answer

Correct option: D

[JEE Main 2019 · 8 Apr · Shift II]

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