The correct order of energies of molecular orbitals of N_2 molecule, is

σ 1s < σ^* 1s < σ 2s < σ^* 2s < (π 2p_x = π 2p_y) < σ 2p_z < (π^* 2p_x = π^* 2p_y) < σ^* 2p_z

σ 1s < σ^* 1s < σ 2s < σ^* 2s < σ 2p_z < (π 2p_x = π 2p_y) < (π^* 2p_x = π^* 2p_y) < σ^* 2p_z

σ 1s < σ^* 1s < σ 2s < σ^* 2s < σ 2p_z < σ^* 2p_z < (π 2p_x = π 2p_y) < (π^* 2p_x = π^* 2p_y)

σ 1s < σ^* 1s < σ 2s < σ^* 2s < (π 2p_x = π 2p_y) < (π^* 2p_x = π^* 2p_y) < σ 2p_z < σ^* 2p_z

The correct order of energies of molecular orbitals of N_2… — NEET 2023 Chemistry PYQ

NEET 2023

The correct order of energies of molecular orbitals of

\text{N}_2

molecule, is

A.
$\sigma 1s < \sigma^* 1s < \sigma 2s < \sigma^* 2s < (\pi 2p_x = \pi 2p_y) < \sigma 2p_z < (\pi^* 2p_x = \pi^* 2p_y) < \sigma^* 2p_z$
B.
$\sigma 1s < \sigma^* 1s < \sigma 2s < \sigma^* 2s < \sigma 2p_z < (\pi 2p_x = \pi 2p_y) < (\pi^* 2p_x = \pi^* 2p_y) < \sigma^* 2p_z$
C.
$\sigma 1s < \sigma^* 1s < \sigma 2s < \sigma^* 2s < \sigma 2p_z < \sigma^* 2p_z < (\pi 2p_x = \pi 2p_y) < (\pi^* 2p_x = \pi^* 2p_y)$
D.
$\sigma 1s < \sigma^* 1s < \sigma 2s < \sigma^* 2s < (\pi 2p_x = \pi 2p_y) < (\pi^* 2p_x = \pi^* 2p_y) < \sigma 2p_z < \sigma^* 2p_z$

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Correct option: A

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