JEE Main 2023 · 25 Jan · Shift 1

JEE Main 2023 Mathematics question on Limits Continuity and Differentiability

The value of lim⁡n→∞1+2−3+4+5−6+......+(3n−2)+(3n−1)−3n2n4+4n+3−n4+5n+4\lim_{n \to \infty} \dfrac{1+2-3+4+5-6+......+(3n-2)+(3n-1)-3n}{\sqrt{2n^4+4n+3}-\sqrt{n^4+5n+4}} is:
  1. A.
    2+12\dfrac{\sqrt{2}+1}{2}
  2. B.
    3(2+1)3(\sqrt{2}+1)
  3. C.
    322\dfrac{3}{2\sqrt{2}}
  4. D.
    32(2+1)\dfrac{3}{2}(\sqrt{2}+1)
Show answer

Correct option: D

[JEE Main 2023 · 25 Jan · Shift 1]

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