lim_t → 0 (1^1/(sin^2 t) + 2^1/(sin^2 t) + … + n^1/(sin^2 t) )^sin^2 t is equal to

lim_t → 0 (1^1/(sin^2 t) + 2^1/(sin^2 t) + … + n^1/(sin^2… — JEE Main 2023 Mathematics PYQ

JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)

\lim_{t \to 0} \left(1^{\frac{1}{\sin^2 t}} + 2^{\frac{1}{\sin^2 t}} + \ldots + n^{\frac{1}{\sin^2 t}}\right)^{\sin^2 t}

is equal to

Show answer

Correct option: D

[JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)]

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