The term independent of x in the expansion of (1/60 - (x^8)/81 ) · (2x^2 - 3/x )^6 is equal to

The term independent of x in the expansion of (1/60 -… — JEE Main 2019 Mathematics PYQ

JEE Main 2019 · 12 April · Shift II

The term independent of

x

in the expansion of

\left(\frac{1}{60} - \frac{x^8}{81}\right) \cdot \left(2x^2 - \frac{3}{x}\right)^6

is equal to

Show answer

Correct option: C

[JEE Main 2019 · 12 April · Shift II]

Practise Binomial Theorem the way it is asked

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