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JEE Main 2019 · 10 April · Shift I

JEE Main 2019 Mathematics question on Binomial Theorem

If the coefficients of x2x^2 and x3x^3 are both zero, in the expansion of the expression (1+ax+bx2)(1−3x)15(1 + ax + bx^2)(1 - 3x)^{15} in powers of xx, then the ordered pair (a,b)(a, b) is equal to
  1. A.
    (28,315)(28, 315)
  2. B.
    (−21,714)(-21, 714)
  3. C.
    (28,861)(28, 861)
  4. D.
    (−54,315)(-54, 315)
Show answer

Correct option: A

[JEE Main 2019 · 10 April · Shift I]

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