JEE Main 2019 · 10 April · Shift I

JEE Main 2019 Mathematics question on Sequences and Series

The sum of series 3×1312+5×(13+23)12+22+7×(13+23+33)12+22+32+…\dfrac{3 \times 1^3}{1^2} + \dfrac{5 \times (1^3 + 2^3)}{1^2 + 2^2} + \dfrac{7 \times (1^3 + 2^3 + 3^3)}{1^2 + 2^2 + 3^2} + \ldots upto 10th term, is
  1. A.
    680
  2. B.
    600
  3. C.
    660
  4. D.
    620
Show answer

Correct option: C

[JEE Main 2019 · 10 April · Shift I]

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