JEE Main 2019 · 11 Jan · Shift II

JEE Main 2019 Mathematics question on Sequences and Series

Let Sn=1+q+q2+...+qnS_n = 1 + q + q^2 + ... + q^n and Tn=1+(q+12)+(q+12)2+...+(q+12)nT_n = 1 + \left(\frac{q+1}{2}\right) + \left(\frac{q+1}{2}\right)^2 + ... + \left(\frac{q+1}{2}\right)^n, where qq is a real number and q≠1q \neq 1. If 101C1+101C2⋅S1+...+101C101⋅S100=αT100^{101}C_1 + ^{101}C_2 \cdot S_1 + ... + ^{101}C_{101} \cdot S_{100} = \alpha T_{100}, then α\alpha is equal to
  1. A.
    21002^{100}
  2. B.
    202202
  3. C.
    200200
  4. D.
    2992^{99}
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Correct option: A

[JEE Main 2019 · 11 Jan · Shift II]

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