The resistance of a wire is . Its new resistance in ohm if stretched to 5 times of its original length will be:
- A.5
- B.625
- C.125
- D.25
Show answer and solution
Correct option: C
Solution
When a wire is stretched to 5 times its original length, its volume remains constant, so the cross-sectional area becomes A/5. Since R = ρL/A, the new resistance scales as (Lnew/Lold) × (Aold/Anew) = 5 × 5 = 25 times the original. Therefore Rnew = 5 × 25 = 125 Ω.
[JEE Main 2023 · 25 Jan · Shift 2]