JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)

JEE Main 2023 Physics question on Current Electricity

As shown in the figure, a network of resistors is connected to a battery of 24V with an internal resistance of 3Ω. The currents through the resistors R4R_4 and R5R_5 are I4I_4 and I5I_5 respectively. The values of I4I_4 and I5I_5 are:

  1. A.
    I4=85I_4 = \frac{8}{5} A and I5=25I_5 = \frac{2}{5} A
  2. B.
    I4=65I_4 = \frac{6}{5} A and I5=245I_5 = \frac{24}{5} A
  3. C.
    I4=25I_4 = \frac{2}{5} A and I5=85I_5 = \frac{8}{5} A
  4. D.
    I4=245I_4 = \frac{24}{5} A and I5=65I_5 = \frac{6}{5} A
Show answer

Correct option: C

[JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)]

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