The magnetic behavior of , and , respectively, are
- A.diamagnetic, diamagnetic and paramagnetic
- B.paramagnetic, paramagnetic and diamagnetic
- C.paramagnetic, diamagnetic and paramagnetic
- D.diamagnetic, paramagnetic and diamagnetic
Show answer and solution
Correct option: A
Solution
Li₂O contains O²⁻ (oxide ion), which has the electron configuration [He]2s²2p⁶ — all electrons paired, so it is diamagnetic.
Na₂O₂ contains O₂²⁻ (peroxide ion), which has a O–O single bond with all electrons paired (bond order 1, no unpaired electrons), so it is diamagnetic.
KO₂ contains O₂⁻ (superoxide ion), which has bond order 1.5 and one unpaired electron in its π* antibonding orbital, making it paramagnetic.
Na₂O₂ contains O₂²⁻ (peroxide ion), which has a O–O single bond with all electrons paired (bond order 1, no unpaired electrons), so it is diamagnetic.
KO₂ contains O₂⁻ (superoxide ion), which has bond order 1.5 and one unpaired electron in its π* antibonding orbital, making it paramagnetic.
[JEE Main 2023 · 29 Jan · Shift 1]