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JEE Main 2019 · 12 Apr · Shift II

JEE Main 2019 Mathematics question on Differential Equations

The general solution of the differential equation (y2−x3)dx−xy dy=0(y^2 - x^3)dx - xy\,dy = 0 (x≠0)(x \neq 0) is (where, CC is a constant of integration)
  1. A.
    y2−2x2+Cx8=0y^2 - 2x^2 + Cx^8 = 0
  2. B.
    y2+2x2+Cx2=0y^2 + 2x^2 + Cx^2 = 0
  3. C.
    y2+2x2+Cx8=0y^2 + 2x^2 + Cx^8 = 0
  4. D.
    y2−2x2+Cx2=0y^2 - 2x^2 + Cx^2 = 0
Show answer

Correct option: B

[JEE Main 2019 · 12 Apr · Shift II]

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