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JEE Main 2019 · 9 Jan · Shift II

JEE Main 2019 Mathematics question on Three Dimensional Geometry

The equation of the plane containing the straight line x2=y3=z4\frac{x}{2} = \frac{y}{3} = \frac{z}{4} and perpendicular to the plane containing the straight lines x3=y4=z2\frac{x}{3} = \frac{y}{4} = \frac{z}{2} and x4=y2=z3\frac{x}{4} = \frac{y}{2} = \frac{z}{3} is
  1. A.
    5x+2y−4z=05x + 2y - 4z = 0
  2. B.
    x+2y−2z=0x + 2y - 2z = 0
  3. C.
    3x+2y−3z=03x + 2y - 3z = 0
  4. D.
    x−2y+z=0x - 2y + z = 0
Show answer

Correct option: D

[JEE Main 2019 · 9 Jan · Shift II]

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