JEE Main 2019 · 10 Jan · Shift I

JEE Main 2019 Mathematics question on Three Dimensional Geometry

Let AA be a point on the line r⃗=(1−3μ)i^+(μ−1)j^+(2+5μ)k^\vec{r} = (1 - 3\mu)\hat{i} + (\mu - 1)\hat{j} + (2 + 5\mu)\hat{k} and B(3,2,6)B(3, 2, 6) be a point in the space. Then, the value of μ\mu for which the vector AB→\overrightarrow{AB} is parallel to the plane x−4y+3z=1x - 4y + 3z = 1 is
  1. A.
    14\dfrac{1}{4}
  2. B.
    −14-\dfrac{1}{4}
  3. C.
    18\dfrac{1}{8}
  4. D.
    12\dfrac{1}{2}
Show answer

Correct option: A

[JEE Main 2019 · 10 Jan · Shift I]

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