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JEE Main 2017

JEE Main 2017 Mathematics question on Three Dimensional Geometry

The distance of the point (1,3,−7)(1, 3, -7) from the plane passing through the point (1,−1,−1)(1, -1, -1) having normal perpendicular to both the lines x−11=y+2−2=z−43\frac{x-1}{1} = \frac{y+2}{-2} = \frac{z-4}{3} and x−22=y+1−1=z+7−1\frac{x-2}{2} = \frac{y+1}{-1} = \frac{z+7}{-1}, is
  1. A.
    2074\frac{20}{\sqrt{74}} units
  2. B.
    1083\frac{10}{\sqrt{83}} units
  3. C.
    583\frac{5}{\sqrt{83}} units
  4. D.
    1074\frac{10}{\sqrt{74}} units
Show answer

Correct option: B

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