lim_n → ∞ ( n/(n^2+1^2) + n/(n^2+2^2) + n/(n^2+3^2) + … + 1/5n ) is equal to

lim_n → ∞ ( n/(n^2+1^2) + n/(n^2+2^2) + n/(n^2+3^2) + … +… — JEE Main 2019 Mathematics PYQ

JEE Main 2019 · 12 Jan · Shift II

\lim_{n \to \infty} \left( \frac{n}{n^2+1^2} + \frac{n}{n^2+2^2} + \frac{n}{n^2+3^2} + \ldots + \frac{1}{5n} \right)

is equal to

Show answer

Correct option: B

[JEE Main 2019 · 12 Jan · Shift II]

Practise Definite Integrals and Areas the way it is asked

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