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JEE Main 2019 · 10 Jan · Shift I

JEE Main 2019 Mathematics question on Definite Integrals and Areas

If the area enclosed between the curves y=kx2y = kx^2 and x=ky2x = ky^2, (k>0)(k > 0), is 1 square unit. Then, kk is
  1. A.
    3\sqrt{3}
  2. B.
    13\dfrac{1}{\sqrt{3}}
  3. C.
    23\dfrac{2}{\sqrt{3}}
  4. D.
    32\dfrac{\sqrt{3}}{2}
Show answer

Correct option: B

[JEE Main 2019 · 10 Jan · Shift I]

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