JEE Main 2019 · 12 Jan · Shift I
JEE Main 2019 Mathematics question on Sequences and Series
Let
Sk=k1+2+3+…+k. If
S12+S22+…+S102=125A, then
A is equal to
- A.
156
- B.
301
- C.
283
- D.
303
Show answer
Correct option: D
[JEE Main 2019 · 12 Jan · Shift I]
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