JEE Main 2019 · 11 Jan · Shift I

JEE Main 2019 Mathematics question on Sequences and Series

Let a1,a2,…,a10a_1, a_2, \ldots, a_{10} be a GP. If a3a1=25\dfrac{a_3}{a_1} = 25, then a9a5\dfrac{a_9}{a_5} equals
  1. A.
    535^3
  2. B.
    2(52)2(5^2)
  3. C.
    4(52)4(5^2)
  4. D.
    545^4
Show answer and solution

Correct option: D

Solution

In a GP with common ratio r, a₃/a₁ = r² = 25, so r = 5.

Then a₉/a₅ = r⁴ = 5⁴.

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