JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.) · numerical answer

JEE Main 2023 Mathematics question on Complex Numbers and Quadratic Equations

Let λ∈R\lambda \in \mathbb{R} and let the equation E be ∣x∣2−2∣x∣+∣λ−3∣=0|x|^2 - 2|x| + |\lambda - 3| = 0. Then the largest element in the set S={x+λ:x is an integer solution of E}S = \{x + \lambda : x \text{ is an integer solution of E}\} is
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Answer: 5

[JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)]

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