Let , and let be the roots of the equation . If , then the product of all possible values of is _______
Show answer and solution
Answer: 45
Solution
Using Vieta's formulas: α + β = -60^(1/4), αβ = a.
Compute α² + β² = (α+β)² - 2αβ = √60 - 2a.
Compute α⁴ + β⁴ = (α²+β²)² - 2(αβ)² = (√60 - 2a)² - 2a² = -30.
Expanding: 60 - 4a√60 + 4a² - 2a² = -30, so 2a² - 4a√60 + 90 = 0, giving a² - 2a√60 + 45 = 0.
By Vieta's for this quadratic in a, the product of all possible values of a = 45.
Compute α² + β² = (α+β)² - 2αβ = √60 - 2a.
Compute α⁴ + β⁴ = (α²+β²)² - 2(αβ)² = (√60 - 2a)² - 2a² = -30.
Expanding: 60 - 4a√60 + 4a² - 2a² = -30, so 2a² - 4a√60 + 90 = 0, giving a² - 2a√60 + 45 = 0.
By Vieta's for this quadratic in a, the product of all possible values of a = 45.
[JEE Main 2023 · 25 Jan · Shift 2]