1993

JEE Main 1993 Mathematics question on Vector Algebra

Let a,b,ca, b, c be distinct non-negative numbers. If the vectors ai^+aj^+ck^a\hat{i} + a\hat{j} + c\hat{k}, i^+k^\hat{i} + \hat{k} and ci^+cj^+bk^c\hat{i} + c\hat{j} + b\hat{k} lie in a plane, then cc is
  1. A.
    the arithmetic mean of aa and bb
  2. B.
    the geometric mean of aa and bb
  3. C.
    the harmonic mean of aa and bb
  4. D.
    equal to zero
Show answer and solution

Correct option: B

Solution

For the three vectors to be coplanar, the scalar triple product must be zero. Setting up the determinant:

|a a c|
|1 0 1| = 0
|c c b|

Expanding: a(0·b - 1·c) - a(1·b - 1·c) + c(1·c - 0·c) = 0

= a(-c) - a(b - c) + c(c) = 0

= -ac - ab + ac + c² = 0

= c² - ab = 0

So c² = ab, which means c is the geometric mean of a and b.

[1993]

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