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JEE Main 2019 · 10 Apr · Shift II

JEE Main 2019 Mathematics question on Three Dimensional Geometry

If Q(0,−1,−3)Q(0, -1, -3) is the image of the point PP in the plane 3x−y+4z=23x - y + 4z = 2 and RR is the point (3,−1,−2)(3, -1, -2), then the area (in sq units) of △PQR\triangle PQR is
  1. A.
    912\dfrac{\sqrt{91}}{2}
  2. B.
    2132\sqrt{13}
  3. C.
    914\dfrac{\sqrt{91}}{4}
  4. D.
    652\dfrac{\sqrt{65}}{2}
Show answer

Correct option: A

[JEE Main 2019 · 10 Apr · Shift II]

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