If is an imaginary cube root of unity, then is equal to
- A.
- B.
- C.
- D.
Show answer and solution
Correct option: D
Solution
Since ω is a primitive cube root of unity, 1 + ω + ω² = 0, so 1 + ω = -ω².
Therefore (1 + ω - ω²) = -ω² - ω² = -2ω².
Raising to the 7th power: (-2ω²)⁷ = -128 · ω¹⁴ = -128 · ω² (since ω³ = 1, so ω¹⁴ = ω²).
The answer is -128ω².
Therefore (1 + ω - ω²) = -ω² - ω² = -2ω².
Raising to the 7th power: (-2ω²)⁷ = -128 · ω¹⁴ = -128 · ω² (since ω³ = 1, so ω¹⁴ = ω²).
The answer is -128ω².
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