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1999

JEE Main 1999 Mathematics question on Complex Numbers and Quadratic Equations

If i=−1i = \sqrt{-1}, then 4+5(−12+i32)334+3(−12+i32)3654 + 5\left(-\dfrac{1}{2} + \dfrac{i\sqrt{3}}{2}\right)^{334} + 3\left(-\dfrac{1}{2} + \dfrac{i\sqrt{3}}{2}\right)^{365} is equal to
  1. A.
    1−i31 - i\sqrt{3}
  2. B.
    −1+i3-1 + i\sqrt{3}
  3. C.
    i3i\sqrt{3}
  4. D.
    −i3-i\sqrt{3}
Show answer

Correct option: C

[1999]

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