If a straight line passing through the point is such that its intercepted portion between the coordinate axes is bisected at , then its equation is
- A.
- B.
- C.
- D.
Show answer and solution
Correct option: B
Solution
If the line has x-intercept (a, 0) and y-intercept (0, b), then P(-3, 4) is the midpoint, so a/2 = -3 and b/2 = 4, giving a = -6, b = 8. The line in intercept form: x/(-6) + y/8 = 1, multiply through by 24: -4x + 3y = 24, i.e., 4x - 3y + 24 = 0.
[JEE Main 2019 · 12 Jan · Shift II]