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JEE Main 2019 · 12 April · Shift II

JEE Main 2019 Mathematics question on Probability

For an initial screening of an admission test, a candidate is given fifty problems to solve. If the probability that the candidate can solve any problem is 45\frac{4}{5}, then the probability that he is unable to solve less than two problem is
  1. A.
    201(15)49201\left(\frac{1}{5}\right)^{49}
  2. B.
    31625(45)48\frac{316}{25}\left(\frac{4}{5}\right)^{48}
  3. C.
    54(45)4954\left(\frac{4}{5}\right)^{49}
  4. D.
    16425(15)48\frac{164}{25}\left(\frac{1}{5}\right)^{48}
Show answer

Correct option: C

[JEE Main 2019 · 12 April · Shift II]

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