Assume that each born child is equally likely to be a boy or a girl. If two families have two children each, then the conditional probability that all children are girls given that at least two are girls; is
- A.
- B.
- C.
- D.
Show answer and solution
Correct option: D
Solution
Total children across two families = 4, each equally likely boy/girl, so 2⁴ = 16 equally likely outcomes.
Event A: all 4 are girls → 1 way → P(A) = 1/16.
Event B: at least 2 are girls → total outcomes minus (0 girls: 1 way) minus (exactly 1 girl: C(4,1)=4 ways) = 16 - 1 - 4 = 11 ways → P(B) = 11/16.
Conditional probability = P(A∩B)/P(B) = (1/16)/(11/16) = 1/11.
Event A: all 4 are girls → 1 way → P(A) = 1/16.
Event B: at least 2 are girls → total outcomes minus (0 girls: 1 way) minus (exactly 1 girl: C(4,1)=4 ways) = 16 - 1 - 4 = 11 ways → P(B) = 11/16.
Conditional probability = P(A∩B)/P(B) = (1/16)/(11/16) = 1/11.
[JEE Main 2019 · 10 Apr · Shift I]