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JEE Main 2013

JEE Main 2013 Chemistry question on Atomic Structure

Energy of an electron is given by
E=−2.178×10−18 J(Z2n2)E = -2.178 \times 10^{-18} \text{ J} \left(\frac{Z^2}{n^2}\right)
Wavelength of light required to excite an electron in an hydrogen atom from level n=1n = 1 to n=2n = 2 will be
(h=6.62×10−34(h = 6.62 \times 10^{-34} Js and c=3.0×108c = 3.0 \times 10^8 ms−1)^{-1})
  1. A.
    (a) 1.214×10−71.214 \times 10^{-7} m
  2. B.
    (b) 2.816×10−72.816 \times 10^{-7} m
  3. C.
    (c) 6.500×10−76.500 \times 10^{-7} m
  4. D.
    (d) 8.500×10−78.500 \times 10^{-7} m
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Correct option: A

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