AIEEE 2008

JEE Main 2008 Mathematics question on Conic Sections

Consider a branch of the hyperbola x2−2y2−22x−42y−6=0x^2 - 2y^2 - 2\sqrt{2}x - 4\sqrt{2}y - 6 = 0 with vertex at the point AA. Let BB be one of the end points of its latusrectum. If CC is the focus of the hyperbola nearest to the point AA, then the area of the △ABC\triangle ABC is
  1. A.
    1−2/31 - \sqrt{2/3} sq unit
  2. B.
    3/2−1\sqrt{3/2} - 1 sq unit
  3. C.
    1+2/31 + \sqrt{2/3} sq unit
  4. D.
    3/2+1\sqrt{3/2} + 1 sq unit
Show answer

Correct option: B

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