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AIEEE 2007

JEE Main 2007 Mathematics question on Conic Sections

A hyperbola, having the transverse axis of length 2sin⁡θ2\sin\theta, is confocal with the ellipse 3x2+4y2=123x^2 + 4y^2 = 12. Then, its equation is
  1. A.
    x2cosec⁡2θ−y2sec⁡2θ=1x^2\cosec^2\theta - y^2\sec^2\theta = 1
  2. B.
    x2sec⁡2θ−y2cosec⁡2θ=1x^2\sec^2\theta - y^2\cosec^2\theta = 1
  3. C.
    x2sin⁡2θ−y2cos⁡2θ=1x^2\sin^2\theta - y^2\cos^2\theta = 1
  4. D.
    x2cos⁡2θ−y2sin⁡2θ=1x^2\cos^2\theta - y^2\sin^2\theta = 1
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Correct option: A

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