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JEE Main 2023 · 29 Jan · Shift 1

JEE Main 2023 Chemistry question on Coordination Compounds

Chiral complex from the following is:
Here en = ethylene diamine
  1. A.
    cis−[PtCl2(NH3)2]cis - [\text{PtCl}_2(\text{NH}_3)_2]
  2. B.
    trans−[Co(NH3)4Cl2]+trans - [\text{Co}(\text{NH}_3)_4 \text{Cl}_2]^+
  3. C.
    cis−[PtCl2(en)2]2+cis - [\text{PtCl}_2(\text{en})_2]^{2+}
  4. D.
    trans−[PtCl2(en)2]2+trans - [\text{PtCl}_2(\text{en})_2]^{2+}
Show answer and solution

Correct option: C

Solution

cis-[PtCl₂(en)₂]²⁺ is an octahedral complex (Pt⁴⁺ with two bidentate en ligands and two Cl⁻). In the cis arrangement, the two Cl ligands are on the same side, and the two en ligands wrap around the metal in a way that the complex has no plane of symmetry and no centre of inversion — it exists as non-superimposable mirror images (Δ and Λ enantiomers). The bidentate nature of en locks the geometry and removes all symmetry elements, making the complex optically active (chiral). The trans isomer, by contrast, has a C₂ axis and mirror planes that make it achiral.

[JEE Main 2023 · 29 Jan · Shift 1]

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