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JEE Main 2023 · 25 Jan · Shift 2

JEE Main 2023 Chemistry question on Practical Chemistry

A chloride salt solution acidified with dil.HNO3\text{HNO}_3 gives a curdy white precipitate, [A], on addition of AgNO3\text{AgNO}_3. [A] on treatment with NH4OH\text{NH}_4\text{OH} gives a clear solution, B.

A and B are respectively
  1. A.
    H[AgCl2]\text{H}[\text{AgCl}_2] & [Ag(NH3)2]Cl[\text{Ag}(\text{NH}_3)_2]\text{Cl}
  2. B.
    AgCl\text{AgCl} & [Ag(NH3)2]Cl[\text{Ag}(\text{NH}_3)_2]\text{Cl}
  3. C.
    AgCl3\text{AgCl}_3 & (NH4)[Ag(OH)2](\text{NH}_4)[\text{Ag}(\text{OH})_2]
  4. D.
    AgCl\text{AgCl} & (NH4)[Ag(OH)2](\text{NH}_4)[\text{Ag}(\text{OH})_2]
Show answer and solution

Correct option: B

Solution

AgCl is the curdy white precipitate formed when Ag⁺ reacts with Cl⁻. When treated with excess NH₄OH (aqueous ammonia), AgCl dissolves because Ag⁺ forms the stable diamminesilver(I) complex ion [Ag(NH₃)₂]⁺, giving the clear solution [Ag(NH₃)₂]Cl. The reaction is: AgCl + 2NH₃ → [Ag(NH₃)₂]⁺ + Cl⁻. This complex formation overcomes the low solubility of AgCl, hence A = AgCl and B = [Ag(NH₃)₂]Cl.

[JEE Main 2023 · 25 Jan · Shift 2]

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