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JEE Advanced 2023 · Paper 1

JEE Advanced 2023 Chemistry question on Redox and Electrochemistry

Plotting 1/Λm1/\Lambda_m against cΛmc\Lambda_m for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with y-axis intercept of P and slope of S. The ratio P/S is

[Λm\Lambda_m = molar conductivity
Λmo\Lambda_m^o = limiting molar conductivity
cc = molar concentration
KaK_a = dissociation constant of HX]
  1. A.
    Ka ΛmoK_a\, \Lambda_m^o
  2. B.
    Ka Λmo/2K_a\, \Lambda_m^o/2
  3. C.
    2 Ka Λmo2\, K_a\, \Lambda_m^o
  4. D.
    1/(Ka Λmo)1/(K_a\, \Lambda_m^o)
Show answer

Correct option: A

[JEE Advanced 2023 · Paper 1]

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