JEE Advanced 2024 · Paper 2 · one or more correct

JEE Advanced 2024 Chemistry question on Redox and Electrochemistry

An aqueous solution of hydrazine (N2H4\text{N}_2\text{H}_4) is electrochemically oxidized by O2\text{O}_2, thereby releasing chemical energy in the form of electrical energy. One of the products generated from the electrochemical reaction is N2(g)\text{N}_2(g).

Choose the correct statement(s) about the above process
  1. A.
    OH−\text{OH}^- ions react with N2H4\text{N}_2\text{H}_4 at the anode to form N2(g)\text{N}_2(g) and water, releasing 4 electrons to the anode.
  2. B.
    At the cathode, N2H4\text{N}_2\text{H}_4 breaks to N2(g)\text{N}_2(g) and nascent hydrogen released at the electrode reacts with oxygen to form water.
  3. C.
    At the cathode, molecular oxygen gets converted to OH−\text{OH}^-.
  4. D.
    Oxides of nitrogen are major by-products of the electrochemical process.
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Correct options: A, C

[JEE Advanced 2024 · Paper 2]

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