JEE Advanced 2024 · Paper 2 · numerical answer

JEE Advanced 2024 Mathematics question on Definite Integrals and Areas

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Let f:[0,π2]→[0,1]f : \left[0, \dfrac{\pi}{2}\right] \to [0,1] be the function defined by f(x)=sin⁡2xf(x) = \sin^2 x and let g:[0,π2]→[0,∞)g : \left[0, \dfrac{\pi}{2}\right] \to [0, \infty) be the function defined by g(x)=πx2−x2g(x) = \sqrt{\dfrac{\pi x}{2} - x^2}.

The value of 16π3∫0π2f(x)g(x)dx\dfrac{16}{\pi^3} \displaystyle\int_{0}^{\frac{\pi}{2}} f(x)g(x)dx is ___________.
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Answer: 0.25

[JEE Advanced 2024 · Paper 2]

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