JEE Advanced 2023 · Paper 1 · one or more correct

JEE Advanced 2023 Mathematics question on Definite Integrals and Areas

Let f:[0,1]→[0,1]f : [0,1] \to [0,1] be the function defined by f(x)=x33−x2+59x+1736f(x) = \dfrac{x^3}{3} - x^2 + \dfrac{5}{9}x + \dfrac{17}{36}. Consider the square region S=[0,1]×[0,1]S = [0,1] \times [0,1]. Let G={(x,y)∈S:y>f(x)}G = \{(x, y) \in S : y > f(x)\} be called the green region and R={(x,y)∈S:y<f(x)}R = \{(x, y) \in S : y < f(x)\} be called the red region. Let Lh={(x,h)∈S:x∈[0,1]}L_h = \{(x, h) \in S : x \in [0,1]\} be the horizontal line drawn at a height h∈[0,1]h \in [0,1]. Then which of the following statements is(are) true?
  1. A.
    There exists an h∈[14,23]h \in \left[\dfrac{1}{4}, \dfrac{2}{3}\right] such that the area of the green region above the line LhL_h equals the area of the green region below the line LhL_h
  2. B.
    There exists an h∈[14,23]h \in \left[\dfrac{1}{4}, \dfrac{2}{3}\right] such that the area of the red region above the line LhL_h equals the area of the red region below the line LhL_h
  3. C.
    There exists an h∈[14,23]h \in \left[\dfrac{1}{4}, \dfrac{2}{3}\right] such that the area of the green region above the line LhL_h equals the area of the red region below the line LhL_h
  4. D.
    There exists an h∈[14,23]h \in \left[\dfrac{1}{4}, \dfrac{2}{3}\right] such that the area of the red region above the line LhL_h equals the area of the green region below the line LhL_h
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Correct options: B, C, D

[JEE Advanced 2023 · Paper 1]

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