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NEET 2025

NEET 2025 Chemistry question on Atomic Structure

Energy and radius of first Bohr orbit of He+\text{He}^+ and Li2+\text{Li}^{2+} are
[Given RH=2.18×10−18 JR_H = 2.18 \times 10^{-18}\,\text{J}, a0=52.9 pma_0 = 52.9\,\text{pm}]
  1. A.
    En(Li2+)=−8.72×10−16 JE_n(\text{Li}^{2+}) = -8.72 \times 10^{-16}\,\text{J};
    rn(Li2+)=17.6 pmr_n(\text{Li}^{2+}) = 17.6\,\text{pm}
    En(He+)=−19.62×10−16 JE_n(\text{He}^+) = -19.62 \times 10^{-16}\,\text{J};
    rn(He+)=17.6 pmr_n(\text{He}^+) = 17.6\,\text{pm}
  2. B.
    En(Li2+)=−19.62×10−18 JE_n(\text{Li}^{2+}) = -19.62 \times 10^{-18}\,\text{J};
    rn(Li2+)=17.6 pmr_n(\text{Li}^{2+}) = 17.6\,\text{pm}
    En(He+)=−8.72×10−18 JE_n(\text{He}^+) = -8.72 \times 10^{-18}\,\text{J};
    rn(He+)=26.4 pmr_n(\text{He}^+) = 26.4\,\text{pm}
  3. C.
    En(Li2+)=−8.72×10−18 JE_n(\text{Li}^{2+}) = -8.72 \times 10^{-18}\,\text{J};
    rn(Li2+)=26.4 pmr_n(\text{Li}^{2+}) = 26.4\,\text{pm}
    En(He+)=−19.62×10−18 JE_n(\text{He}^+) = -19.62 \times 10^{-18}\,\text{J};
    rn(He+)=17.6 pmr_n(\text{He}^+) = 17.6\,\text{pm}
  4. D.
    En(Li2+)=−19.62×10−16 JE_n(\text{Li}^{2+}) = -19.62 \times 10^{-16}\,\text{J};
    rn(Li2+)=17.6 pmr_n(\text{Li}^{2+}) = 17.6\,\text{pm}
    En(He+)=−8.72×10−16 JE_n(\text{He}^+) = -8.72 \times 10^{-16}\,\text{J};
    rn(He+)=26.4 pmr_n(\text{He}^+) = 26.4\,\text{pm}
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Correct option: B

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