NEET 2025

NEET 2025 Physics question on Rotational Motion

A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 60° with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (Take g=10 m/s2g = 10\,\text{m/s}^2)
  1. A.
    2003 N200\sqrt{3}\,\text{N}
  2. B.
    100 N100\,\text{N}
  3. C.
    1003 N100\sqrt{3}\,\text{N}
  4. D.
    200 N200\,\text{N}
Show answer

Correct option: C

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