NEET 2020 Physics question on Electrostatics

A short electric dipole has a dipole moment of $16 \times 10^{-9}\,\text{C m}$. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is : $\left(\dfrac{1}{4\pi\varepsilon_0} = 9 \times 10^9\,\text{N m}^2/\text{C}^2\right)$