When is heated in presence of oxygen, it converts to . The number of correct statement/s from the following is __________
A. The equivalent weight of is
B. The number of moles of and in 1 mole of is 0.79 and 0.14 respectively
C. is metal deficient with lattice comprising of cubic closed packed arrangement of ions
D. The % composition of and in is 85% and 15% respectively
A. The equivalent weight of is
B. The number of moles of and in 1 mole of is 0.79 and 0.14 respectively
C. is metal deficient with lattice comprising of cubic closed packed arrangement of ions
D. The % composition of and in is 85% and 15% respectively
Show answer and solution
Answer: 4
Solution
## Key Analysis of Fe₀.₉₃O
Finding Fe²⁺ and Fe³⁺ composition:
Let x = moles of Fe³⁺, then (0.93 - x) = moles of Fe²⁺ in 1 mole of Fe₀.₉₃O.
Charge balance: 2(0.93 - x) + 3x = 2(1) [since O²⁻ contributes 2⁻]
1.86 - 2x + 3x = 2 → x = 0.14
So Fe³⁺ = 0.14 mol, Fe²⁺ = 0.79 mol ✓ (Statement B is correct)
Checking Statement A (equivalent weight):
The n-factor of Fe₀.₉₃O when converted to Fe₂O₃: each Fe²⁺ loses 1 electron, so total electrons lost per formula unit = 0.79 × 1 = 0.79. Equivalent weight = Molecular weight/0.79 ✓ (Statement A is correct)
Checking Statement D (% composition):
% Fe²⁺ = (0.79/0.93) × 100 = 84.9% ≈ 85%, % Fe³⁺ = (0.14/0.93) × 100 = 15% ✓ (Statement D is correct)
Checking Statement C:
Wüstite (Fe₀.₉₃O) does have a rock-salt structure with **cubic close-packed O
Finding Fe²⁺ and Fe³⁺ composition:
Let x = moles of Fe³⁺, then (0.93 - x) = moles of Fe²⁺ in 1 mole of Fe₀.₉₃O.
Charge balance: 2(0.93 - x) + 3x = 2(1) [since O²⁻ contributes 2⁻]
1.86 - 2x + 3x = 2 → x = 0.14
So Fe³⁺ = 0.14 mol, Fe²⁺ = 0.79 mol ✓ (Statement B is correct)
Checking Statement A (equivalent weight):
The n-factor of Fe₀.₉₃O when converted to Fe₂O₃: each Fe²⁺ loses 1 electron, so total electrons lost per formula unit = 0.79 × 1 = 0.79. Equivalent weight = Molecular weight/0.79 ✓ (Statement A is correct)
Checking Statement D (% composition):
% Fe²⁺ = (0.79/0.93) × 100 = 84.9% ≈ 85%, % Fe³⁺ = (0.14/0.93) × 100 = 15% ✓ (Statement D is correct)
Checking Statement C:
Wüstite (Fe₀.₉₃O) does have a rock-salt structure with **cubic close-packed O
[JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)]