Two objects are projected with same velocity 'u' however at different angles and with the horizontal. If , the ratio of horizontal range of the first object to the 2nd object will be:
- A.1 : 1
- B.1 : 2
- C.2 : 1
- D.4 : 1
Show answer and solution
Correct option: A
Solution
The horizontal range formula is R = u²sin(2θ)/g. For angles α and β where α + β = 90°, we have β = 90° - α, so sin(2β) = sin(2(90°-α)) = sin(180°-2α) = sin(2α). Both ranges are equal, giving ratio 1:1.
[JEE Main 2023 · 25 Jan · Shift 2]