1982
JEE Main 1982 Mathematics question on Limits Continuity and Differentiability
There exists a function
f(x) satisfying
f(0)=1,
f′(0)=−1,
f(x)>0,
∀x and
- A.
f′′(x)<0,
∀x - B.
−1<f′′(x)<0,
∀x - C.
−2≤f′′(x)≤−1,
∀x - D.
f′′(x)<−2,
∀x
Show answer
Correct option: A
[1982]
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