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JEE Main 2019 · 12 Apr · Shift I

JEE Main 2019 Mathematics question on Inverse Trigonometric Functions

The value of sin⁡−1(1213)−sin⁡−1(35)\sin^{-1}\left(\dfrac{12}{13}\right) - \sin^{-1}\left(\dfrac{3}{5}\right) is equal to
  1. A.
    π−sin⁡−1(6365)\pi - \sin^{-1}\left(\dfrac{63}{65}\right)
  2. B.
    π2−sin⁡−1(5665)\dfrac{\pi}{2} - \sin^{-1}\left(\dfrac{56}{65}\right)
  3. C.
    π2−cos⁡−1(965)\dfrac{\pi}{2} - \cos^{-1}\left(\dfrac{9}{65}\right)
  4. D.
    π−cos⁡−1(3365)\pi - \cos^{-1}\left(\dfrac{33}{65}\right)
Show answer

Correct option: B

[JEE Main 2019 · 12 Apr · Shift I]

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