1991
JEE Main 1991 Mathematics question on Limits Continuity and Differentiability
The value of
limx→0x21(1−cos2x) is
- A.
1
- B.
-1
- C.
0
- D.
None of these
Show answer
Correct option: D
[1991]
More: all JEE Main Limits Continuity and Differentiability questions · JEE Main 1991 · Mathematics chapter list