The trajectory of a projectile near the surface of the… — JEE Main 2019 Physics PYQ

JEE Main 2019 · 19 May · Shift I

The trajectory of a projectile near the surface of the earth is given as

y = 2x - 9x^2

.

If it were launched at an angle

\theta_0

with speed

v_0

, then (Take,

g = 10

^{-2}

)

A.
$\theta_0 = \sin^{-1}\left(\dfrac{1}{\sqrt{5}}\right)$ and $v_0 = \dfrac{5}{3}$ ms $^{-1}$
B.
$\theta_0 = \cos^{-1}\left(\dfrac{1}{\sqrt{5}}\right)$ and $v_0 = \dfrac{2}{3}$ ms $^{-1}$
C.
$\theta_0 = \cos^{-1}\left(\dfrac{1}{\sqrt{5}}\right)$ and $v_0 = \dfrac{5}{3}$ ms $^{-1}$
D.
$\theta_0 = \sin^{-1}\left(\dfrac{1}{\sqrt{5}}\right)$ and $v_0 = \dfrac{3}{2}$ ms $^{-1}$

Show answer

Correct option: C

[JEE Main 2019 · 19 May · Shift I]

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JEE Main 2019 Physics question on Kinematics