JEE Main 2019 · 9 Jan · Shift II

JEE Main 2019 Mathematics question on Sequences and Series

The sum of the following series
1+6+9(12+22+32)7+12(12+22+32+42)9+15(12+22+⋯+52)11+… up to 15 terms is1 + 6 + \frac{9(1^2 + 2^2 + 3^2)}{7} + \frac{12(1^2 + 2^2 + 3^2 + 4^2)}{9} + \frac{15(1^2 + 2^2 + \cdots + 5^2)}{11} + \ldots \text{ up to 15 terms is}
  1. A.
    7510
  2. B.
    7820
  3. C.
    7830
  4. D.
    7520
Show answer

Correct option: B

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